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Suppose that, out of a total of 572 full-service restaurants in Vermont, the number of seats per restaurant is normally distributed with mean µ=65.7 and a standard deviation σ=20.5
The Vermont tourism board selects a simple random sample of 50 full-service restaurants located within the state and determines the mean number of seats per restaurant for sample.
What is the standard deviation of the sampling distribution of the sample mean?
There is a .25 probability that the sample mean is less than __________.
the mean annual income of certified welders is normally distributed with a mean of 50000 and a population standard
Use the following information from a normal population with mean μ = 52 and variance σ2 = 22.5 to calculate the following questions.
a random sample of size 38 is chosen from a population with an unknown mean and variance. the sample mean and standard
Specify the appropriate null and alternative hypotheses if we wish to test the research hypothesis that the mean GHQ score for all employed men exceeds 10.
Assume that the result is a sample size beyond what you can obtain. Use the compromise function to compute alpha and beta for a sample approximately half the size.
A random sample of 61 accounts were checked. The standard deviation was $286.20. At α= 0.01, test the firms' assumption. Assume the account balances are normally distributed.
A firm has tendered for two independent contracts. It estimates that it has probability 0.4 of obtaining contract A, and probability 0.1 of obtaining contract B. Find the probability that the firm:
supposed that a b and c are mutually independent events and that pa0.5 pb0.8 and pc0.9. find the probabilities that
How is the null hypothesis chosen (why is it null)? What is the importance of rejecting the null hypothesis in relation of the sample to the population?
The maximum allowable payback and discounted payback statistic for the project are 2 and 2.5 years, respectively. Use the NPV decision rule to evaluate this project; should it be accepted or rejected?
Find the mean and median of the transformed heights and convert the mean and median of the transformed data back to the original units.
it has been reported that 80 of all email received is junk mail. each morning a computer user turns on his computer and
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