Standard deviation of no-shows

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Reference no: EM1399833

In an attempt to minimize no-shows on high-demand days a golf course has implemented an online check-in procedure. Preliminary results indicate that once a golfer has checked in, there is only at 20% chance that he or she will be a no-show. This chance of being a no-show can be modeled using the binomial distribution.

If 15 golfers have checked in using this process, what is the probability there will be exactly 4 no-shows among them? (Use the formula, show work)

If 15 golfers have checked in using this process, what is the probability there will be at least 4 no-shows among them? (Use calculator, write down the command - all details)

If 15 golfers have checked in using this process, what is the expected number and standard deviation of no-shows among these golfers? (Show computations)

Reference no: EM1399833

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