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Represent the proportion of all medical doctors

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A random sample of 328 medical doctors showed that 178 had a solo practice.

(a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.)

(b) Find a 98% confidence interval for p. (Use 3 decimal places.)lower limitupper limit

Give a brief explanation of the meaning of the interval.

2% of the all confidence intervals would include the true proportion of physicians with solo practices.

2% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.

98% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.

98% of the all confidence intervals would include the true proportion of physicians with solo practices.

(c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice?

Report p^ along with the margin of error.

Report the confidence interval.

Report the margin of error.

Report p^.

What is the margin of error based on a 98% confidence interval? (Use 3 decimal places.)

Reference no: EM132464873

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