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In a study of a proposed treatment for diabetes prevention, 339 people under the age of 20 who were thought to be at high risk of developing type I diabetes were assigned at random to two groups. One group received twice-daily injections of a low dose of insulin. The other group (the control) did not receive any insulin, but was closely monitored. Summary data (from the article "Diabetes Theory Fails Test," USA Today, June 25, 2001) follow.
a. Use the given data to construct a 90% confidence interval for the difference in the proportion that develop diabetes for the control group and the insulin group.
b. Give an interpretation of the confidence interval and the associated confidence level.
c. Based on your interval from Part (a), write a few sentences commenting on the effectiveness of the proposed prevention treatment.
Marital Status. The probability that a randomly chosen 40-year-old woman is divorced is about 0.15. this probability is a long-run proportion based on all the millions of women aged 40.
Assume that in a hypothesis test with null hypothesis H 0 : μ = 14.0 at a = 0.05, that a value of 13.0 for the sample mean results in the null hypothesis not being rejected. That corresponds to a confidence interval result of:
Given that x is a normal variable with mean u = 47 and standard deviation = 6.2, find:
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The researcher found that Lincoln's educational score did not correlate with the expected variables.
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Other questions we might want to ask about pooling similar populations: Do all the subpopulations have the same ratio of yellow to green seeds? Does the average ratio deviate from our hypothesized ratio?
Imagine you are a manager at a major bottling company. Customers have begun to complain that the bottles of the brand of soda produced in your company contain less than the advertised sixteen (16) ounces of product.
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An article that appeared in USA Today (September 3, 2003) included a graph similar to the one shown here summarizing responses from polls conducted
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