Reference no: EM132331630

1. Make a program that accepts an integer input from the user and display the least number of combinations of 200s, 100s, 50s, 20s, 10s, 5s, and 1s.

[Test your solution using this samples]

a. Input: 250

Output: 1x200s, 1x50s

b. Input: 1127

Output: 5x200s, 1x100s, 1x20s, 1x5s, 2x1s

c. Input: 1127

Output: 5x200s, 1x100s, 1x20s, 1x5s, 2x1s

d. Input: 19

Output: 1x10s, 1x5s, 4x1s

[Hints]

• Use division to determine the number of occurrence of each element (i.e. 200, 100) in the input (e.g. Given 500 if we divide it by the largest number possible; which is 200; we will get 2. Therefore, there are 2x200s.)
• Use subtraction to determine the remaining value of the input. (e.g. In the 500 example, since there are 2x200s, we still have 100 to process. The 100 came from 500 - (2*200) = 100.)
• Use the next largest number possible (i.e. 100) to check the number of occurrence. Continue until the remaining value of the input is zero.

2. Make a program that accepts the firstname and the lastname of the user, and display the first half of the lastname, first half of the firstname, second half of the lastname and second half of the firstname.

[Test your solution using this samples]

a. Firstname Input: Juan

Lastname Input: DelaCruz

Output: DelaJuCruzan

b. Firstname Input: Pedro

Lastname Input: Penduko

Output: PendPedukoro

c. Firstname Input: Johann

Lastname Input: Logan

Output: LogJohanann

d. Firstname Input: Mari

Lastname Input: Santamaria

Output: SantaMamariari

[Hints]

• To determine the first half of the name, you can use name[0, lengthOfName/2]
• To determine the second half of the name, you can use name[lengthOfName/2, lengthOfName]
• To determine the length of the name, you can use lengthOfName = GetLength(name)