Probability that an aggressive approach was used

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Reference no: EM132025133

In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a customer a new automobile: the aggressive approach and the passive approach. For 1160 customers, the following record was kept: 

Sale  No Sale  Row Total 

Aggressive  278 302 580

Passive  493 87 580

Column Total  771 389 1160

Suppose a customer is selected at random from the 1160 participating customers. Let us use the following notation for events: A = aggressive approach, Pa = passive approach, S = sale, N = no sale. So, P(A) is the probability that an aggressive approach was used, and so on.

(a) Compute 

P(S), =

P(S | A),=

P(S | Pa). =

(Enter your answers as fractions.)

(b) Are the events S = sale and Pa = passive approach independent? Explain.

Yes. P(S) = P(S | Pa).

No. P(S) ≠ P(S | Pa).    

Yes. The two events can occur together.

No. The two events cannot occur together.

(c) Compute P(A and S) and P(Pa and S). (Enter your answers as fractions.)P(A and S) = P(Pa and S) = 

(d) Compute P(N) and P(N | A). (Enter your answers as fractions.)P(N) = P(N | A) = 

(e) Are the events N = no sale and A aggressive approach independent? Explain.

Yes. The two events can occur together.

Yes. P(N) = P(N | A). 

No. The two events cannot occur together.

No. P(N) ≠ P(N | A).

(f) Compute P(A or S). (Enter your answer as a fraction.)

P(A or S) = 

Reference no: EM132025133

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