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Cashier records from the last year that 35% of all Ralph's grocery store customers use a previously-obtained Ralph's discount card upon checkout. Management suspects the percentage of actual cardholders is higher because some customers may not use their Ralph's during every visit. They decide to sample random customers who enter the store, and ask them if they have a Ralph's card. Suppose they solicit 400 customers one day, and find that 160 of the have a Ralph's card.
Assuming for a moment that 35% of all Ralph's customers have a discount card, what is the probability of getting a sample proportion at least this big? U (round to 2 decimal places)=, Q (round to 4 decimal places)=, Probability (round to 4 decimal places)?
Two colored dice are tossed. What is the probability that the sum of the numbers shown on the upper faces is equal to 7?
A sample of 40 random weeks finds a weekly loss mean of $3200 with a standard deviation of $750. Test their claim at the a=0.05 level.
Suppose normality, determine a 90% confidence interval for population variance.
A recent article in Vitality magazine reported that the mean amount of leisure time per week for American men is 40.0 hours. You believe this figure is too large and decide to conduct your own test.
Chance that David would default on his loan based on your knowledge about David. At a cost of about $1000, the bank can investigate and figure out David's complete credit history.
We conclude that memory of food intake in the distant past is fair to poor." Explain to your audience why r=0.217 points to this conclusion.
A pharmaceutical company has determined that if a new cholesterol-reducing drug is manufactured (introduced to the market) the following probability distribution will describe this drug's contribution to the company profits during the next six mon..
The instructor wanted to "pass" anyone who scored above 69. What proportion of exams will have passing scores?
One-fourth of the residents of the Burning Ridge Estates leave their garage doors open when they are away from home. The local chief of police estimates that 5 percent of the garages with open doors will have something stolen
The 97.5% CI for mean changes in Group B minus mean change in Group A is (-4.7 to -0.9). Suppose we want to compute a two-sided p-value to compare the two groups.
Indicate your hypotheses, decision rule, statistical decision and management conclusion using the critical value and then find the p-value and state your decision rule, statistical decision and management conclusion using this method.
As it is a 2 × 2 table, try also two-tailed two-sample z test for π 1 = π 2 and verify that z 2 is same as your chi-square statistic. Which test do you prefer? Explain why?
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