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Question :
Write a program pyramid.cpp that reads a positive odd whole number n and prints a pyramid where the last row contains all numbers from n down to 1 (i.e., descending order), the second to last row displays all numbers from n - 1 down to 2, the third to last row displays all numbers from n - 2 down to 3, etc.
The first row will contain only a single value, i.e. the middle value in the range, i.e. n down to 1.
Each successive row contains two more values than the previous row. This is the original problem , I WANT TO INVERSE the picture, here is my code, I don't know where is wrong? #include using namespace std;
int main(){
int n;
cout << "Enter n : ";
cin >> n;
int mid = (n+1)/2;
for(int i =1;i<=mid;i++){
for(int j=1;j<=i;j++){
cout << " ";}
int a=n; int bb=n; for(int h=bb;h>=1;h--){
if((a-i+1)>=10){
cout << (a-i+1)%10;}
else{ cout << a-i+1; }
a--; }
cout << endl;
bb = bb-2; }
return 0; }
The result runs the same as the original problem.
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