Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
An earlier study claims that U.S. adults spend an average of 114 minutes with their families per day. A recently taken sample of 25 adults showed that they spend an average of 109 minutes per day with their families. The sample standard deviation is 11 minutes. Assume that the time spent by adults with their families has an approximate normal distribution. We wish to test whether the mean time spent currently by all adults with their families is less than 114 minutes a day.
a) Set up the null and alternative hypotheses, and perform the hypothesis test with a significance level of 0.05.
b) Does the sample information support that the mean time spent currently by all adults with their families is less than 114 minutes a day? Explain your conclusion in words.
A survey of college students collected information on several variables: Distance from Home, Age, Major, Gender, and Class. The variable Major is
Let A be the event that a randomly chosen employee has a college degree and B the event that the chosen employee's income is more than $50,000.
A random sample of 58 fish is taken from the tank. Let x be the mean sample length of these fish. What is the probability that x is within 0.5 inch of the claimed population mean? (Round your answer to four decimal places.)
Use this information to set up a 90 percent confidence interval for the proportion, p of all US workers who play hooky.
Absenteeism is distributed evenly throughout the week. The 0.01 level is to be used. The sample results are:
Is there evidence of difference in median performance between two methods? (Use α = 0.05.)
In the biology class the mean score was 79 with standard deviation 5.
In terms of the standard scores for both sections, the score of which section was better? What are the z-scores for both sections?
Suppose the people have weights that are normally distributed with a mean of 164lb and a standard deviation of 30lb. Find the probability?
What is the probability there will be between 10 and 14 calls inclusive arriving at the company in the next 15 minutes?
Calculate the mean and standard deviation of the sample mean based on data from 100 stores.
Compute the variance and standard deviation of the number that will arrive within two days.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd