Organic chemistry, RATIO: yield secondary Hydrogen/yield of

Organic chemistry

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Reference no: EM13962576

Organic Chemistry:

For PROPANE (CH₃CH₂CH₃)

RATIO: yield secondary Hydrogen/yield of primary hydrogen = 2/6 *4.5 = 1.5 therefore secondary:primary ration = 1.5:1

60% Secondary product & 40% primary product

My question is - The percentages above (60% & 40%) how do we calculate these???

Reference no: EM13962576

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