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Assume that female students' heights are normally distributed with a mean given by µ = 67.2 in. and a standard deviation given by σ = 3.6 in.
1) If one female student is randomly selected, find the probability that her height is above 63.0 in.
2) If 100 female students are randomly selected, find the probability that they have a mean height greater than 63.0 in.
Bougainvilleas, mean growth rate was 2.23 inches/week and sample standard deviation was 0.77 inches/week. Determine a 90% confidence interval for mean growth rate of all Bougainvilleas.
What sample size would be required to obtain the error of ±10 square millimeters with 99 percent confidence?
Create a 95 % confidence interval for the true mean. Why might normality be the issue here?
Find the percentage of the 1000 enemy that will be destroyed.
Is the z value positive or negative? Explain why it should be positive or negative.
Whenever the calculated value of t is equal to or greater than the tabled value of t, for a given number of degrees of freedom, then
Finding an X score. All Bright University will consider an applicant for its MBA program who scores 95 percent or higher on the GMAT exam. The mean and standard deviation, respectively, for this test are 578 and 94. What is the lowest score (X) th..
Identify a research question from your professional life, research interests, or everyday experience that could be addressed by this analysis.
Consider a binomial distribution with 15 identical trials, and a probability of success of 0.5. Use the normal approximation to find the probability that x = 2.
Normal approximation to the Binomial distribution - Evaluate the probability that at least 195 of the students are female.
Determine the shape of chi-square distribution?
What is the probability that the mean weight for a sample of 40 trout exceeds 405.5 grams?
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