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A tire company test a particular model of tire and found the tires to be normally distributed with respect to wear. The mean was 28,000 miles and the standard deviation was 2500 miles. If 2000 tires are tested, about how many are likely to wear out before 23,000 miles.
Determine following probabilities where Z follows standard Normal distribution?
Determine the number of successes suggested by the given statement.
If the true mean for Saturday sales is now $4500, what is the probability of accepting the (false) null hypothesis in (a) above (the probability of not sharing the manager's concern because of lack of evidence)?
Exam is given to 20 randomly chosen students and their average length of t time needed to finish exam was 54 minutes with standard deviation of 5.99 minutes. Test instructor's claim at the 0.05 level of significance.
Indicate which would be the independent variable and which would be the dependent variable in each of the following:
Use the value 20 for the population standard deviation of scores on this subsection.
Florida State University administers a mathematics placement test to students where they 1st enter the university.
Utilize a test of the difference among proportions when answering these questions. Illustrate the research hypothesis.
Assume the population standard deviations are not the same. At the .05 significance level, is there a difference in the mean waiting time?
Based on these data, does it seem that strength of relationship between sales and promotions expenditures is enough to permit using linear regression forecasting model? Describe why?
Assuming the sample size of 40 can be considered as large, compute the confidence interval for a confidence level of 90%.
No, there is not sufficient information to reject the hypothesis that the proportion of cats and the proportion of dogs that sleep more than 10 hours per day are the same because the test value -0.65 is inside the acceptance region (-1.96,1.96).
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