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Question 1Select one answer.CRP protein binds to the lac operon under conditions of low glucose. Its role in the expression of genes in the lac operon is:A. to transcribe DNA to mRNA for the structural genes in the operator.B. It increases the binding of lactose to the lac repressor, causing it to be released from the operator.C. It enhances the binding of RNA polymerase to the lac operon, increasing transcriptionD. It bumps the lac repressor off the DNA, allowing transcription of the genes for lactose metabolism.Question 2Select one answer.Which of the following refers to variations in the same gene, which result in different phenotypes?A. ChromosomeB. DNAC. AlleleD. GenotypeQuestion 3Select one answer.When bacteria are grown in lactose they produce enzymes required for lactose metabolism. When placed in glucose, these enzymes are no longer produced. The expression of these genes is likely due to:A. Uncondensing of the DNA, to allow for expression of the genes.B. mutations accumulated in the regulatory region of the gene that code for lactose metabolizing enzymes.C. Changing the behavior of a DNA binding protein that regulates expression of these genes.Question 4Select one answer.Eukaryotic DNA is packaged into nucleosomes due to the action ofA. histonesB. DNA helicasesC. repressor proteinsD. RNA polymerasesQuestion 5Select one answer.In what type of cell do genes contain exons which are interrupted by introns, that are spliced out after transcription.A. ProkaryoticB. EukaryoticC. Both prokaryotic and eukaryotic cells.Question 6Select one answer.Assuming that the genes required for sucrose (table sugar) degradation are contained within an operon, then under conditions of low sucrose, you would expect:A. The repressor protein to bind to the operator, preventing transcription.B. The repressor protein to bind to the operator, allowing transcription.C. The repressor protein released from the operator, allowing transcription.D. The repressor protein released from the operator, preventing transcription.Question 7Select one answer.Which of the following represents a change that CANNOT be passed on to the next generation?A. Changes in gene expression due to increased production of a hormone.B. Changes in DNA packaging leading to gene silencing.C. Changes in DNA sequence due to exposure to radiation.D. None of the above, they are all heritable changes.Question 8Select one answer.DNA resides in the nucleus of the cell in a prokaryotic cell, but not a eukaryotic cell.A. TrueB. False
Suppose that a series of compounds has been found in Neurospora . Compounds A-F appear to be members of an enzyme pathway.
Briefly describe three specific aspects of transpiration and phloem transport that involve active transport of molecules.
What veins are most likely involved? What pathologic changes have happened in these veins, and what is the most probable cause in this patient's case.
Explain how penetrance and expressivity can affect the expression of an allele and how epigenetic phenomena affect the observed pattern of inheritance.
What fraction of demes in each set is likely to become fixed for allele A1 versus A2. Explain the differences in head movement available to fish.
At start of abduction of arm, deltoid muscle is assisted by: subclavius., supraspinatus, coracobrachialis, Biceps brachii.
Certain unscrupulous operators offer, for a fee, to freeze recently deceased individuals in liquid nitrogen until medical science can cure the disease from which they died. What is the biochemical fallacy of this process.
Diploid nuclei of the ascomycete, Neurospora crassa, contain 14 chromosomes. A single diploid cell in an ascus will undergo one round of meiosis, followed in each of daughter cells by one round of mitosis, producing a total of eight ascospores.
A new reality TV show includes a "contest" to survive solitary confinement. To win, the contestant must remain for 12 hours in an air-tight room that is 5ft X 5ft X 8 ft.
When a nucleic acid undergoes hydrolysis, resulting subunits
A 2.5 mg/ml stock solution was diluted as described in the table below and then the absorbance of each dilution was estimated and presented in the table given below.
BIOL 6150 home work, Linkage disequilibrium and LOD score, Assume the disease genotype is known, as A is the disease allele and a is the normal allele. The marker has four alleles (1, 2, 3,4).
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