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Determine the estimated mean of the following frequency distribution.
Class Frequency
20 up to 30 7
30 up to 40 12
40 up to 50 21
50 up to 60 18
60 up to 70 12
A sample of the amounts paid for parking on Saturday at the Downtown Parking Garage in Toronto was organized into the following frequency distribution.
Amount Paid Frequency
$0.50 up to $0.75 2
0.75 up to 1.00 7
1.00 up to 1.25 15
1.25 up to 1.50 28
1.50 up to 1.75 14
1.75 up to 2.00 9
2.00 up to 2.25 3
2.25 up to 2.50 2
The heights of young women are approximately normal with mean 65 inches and standard deviation 2.5 inches.
Does the data prove a significant difference in mean times?
Calculate expected number of interruptions per day. Calculate standard deviation.
Find a 95% confidence interval for the population mean selling price of all homes in this neighborhood.
Construct a 90% two-sided confidence interval onthe difference between the proportion nonconforming in processes 1 and 2. Based on this confidence interval, can you conclude at a significance level of 10% that the difference is not equal to 10%? W..
write down the hypothesis the test used the p-value and the interpretation then hand calculates a 95% CL for the odds ratio estimate on this last test.
After performing a two sample t-test, you see a p-value of 0.0355. Of the following, which is the appropriate conclusion?
An automotive expert claims that the large number of self-serve gasoline stations has resulted in poor automobile maintenance, and that the average tire pressure is more than 4 pounds per square inch (psi) below its manufacturer's specification.
Assume a population standard deviation of 450-kilowatt hours. Determine the standard error of the mean.
Stating assumptions on which your arguments and conclusions are based, sum up the statistical evidence regarding effectiveness of this diet.
How large a sample is required to estimate the mean speed with a margin of error equal to 2 miles per hour with 90% confidence?
Records also point to that interviewing committee of bank officers approves 85% of individuals they interview. Determine probability that Ann's loan request is approved.
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