Reference no: EM13529901
1. Find the value of the polynomial –x2 + 4x + 10 when x = –2.
A) 6 B) –22 C) –2 D) 14
3. Simplify. (a7b2)7
A) a7b14 B) a49b14 C) a14b9 D) a7b9
4. Multiply. (5a – 3b)2
A) 25a2 – 30ab – 9b2 B) 25a2 + 9b2 C) 25a2 – 9b2 D) 25a2 – 30ab + 9b2
6. Multiply. (–5x + 4)2
A) 25x2 – 20x + 16 B) 25x2 + 16 C) 25x2 – 40x + 16 D) –5x2 – 20x + 16
8. Remove the parentheses. –(4m – 3n)
A) –4m – 3n B) –4m + 3n C) 4m + 3n D) 4m – 3n
9. Multiply. (4m – 3n)(4m + 3n)
A) 16m2 – 9n2 B) 16m2 + 9n2 C) 16m2 + 24mn – 9n2 D) 16m2 – 24mn + 9n2
10. Evaluate (assume x != 0).
–10x0
A) 1 B) –10x C) 0 D) –10
12. Multiply. –3x(10x + 9)
A) –57x2 B) 30x2 – 27x C) –30x2 + 9x D) –30x2 – 27x
14. Add 5y – 4 and 2y2 – 8y.
A) 7y2 – 12y – 4 B) 2y2 – 3y – 4 C) 2y2 + 13y – 4 D) 2y2 + 3y – 4
15. What is the degree of the polynomial x12 – 5x4?
A) 4 B) 5 C) 12 D) –5
16. Determine which of the ordered pairs are solutions for the equation.
x – 4y = 7
A) (–1, –2), (15, 4), (13, –5), (15, 2)
B) (–1, –2), (23, 4), (–13, –5), (15, 2)
C) (–1, –2), (23, 4), (15, –5), (–13, 2)
D) (–1, –2), (23, 4), (–13, –5), (–15, 2)
17. Complete the ordered pairs so that each is a solution for the equation.
3x + 4y = 10 (2, __ ), ( __ , 7), (–2, __ ), ( __ , –5)
A) (2, –1), (–6, 7), (–2, –4), (10, –5)
B) (2, 4), (–6, 7), (–2, 1), (10, –5)
C) (2, 1), (–6, 7), (–2, 4), (10, –5)
D) (2, 1), (4, 7), (–2, 4), (1, –5)
20. Is the pair of lines parallel, perpendicular, or neither?
L1 through (–2, –3) and (0, 5); L2 through (2, –1) and (–4, 7);
A) parallel
B) perpendicular
C) neither
21. Is the pair of lines parallel, perpendicular, or neither?
L1 through (3, 4) and (–1, 8); L2 through (–1, 0) and (3, 4)
A) parallel
B) perpendicular
C) neither
22. Write the equation of the line passing through (–5, 14) with the slope –2.
A) y = –2x + 10
B) y = –2x + 4
C) y = –1/2 x + 4
D) y = –2x + 6