Initial step in the catabolism of glucose

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Reference no: EM132439634

The phosphorylation of glucose to glucose 6-phosphate is the initial step in the catabolism of glucose. The direct phosphorylation of glucose by Pi is described by the equation

Glucose + P i → glucose 6-phosphate + H 2O        Δ G′e ° = 13.8 kJ/mol

(a) Calculate the equilibrium constant for the above reaction at 25 °C. In the rat hepatocyte the physiological concentrations of glucose and Pi are maintained at approximately 4.8 mm. What is the equilibrium concentration of glucose 6-phosphate obtained by the direct phosphorylation of glucose by Pi? Does this reaction represent a reasonable metabolic step for the catabolism of glucose? Explain.

(b) In principle, at least, one way to increase the concentration of glucose 6-phosphate is to drive the equilibrium reaction to the right by increasing the intracellular concentrations of glucose and Pi. Assuming a fixed concentration of Pi at 4.8 mm, how high would the intracellular concentration of glucose have to be to give an equilibrium concentration of glucose 6-phosphate of 250 μm (the normal physiological concentration)? Would this route be physiologically reasonable, given that the maximum solubility of glucose is less than 1 m?

(c) The phosphorylation of glucose in the cell is coupled to the hydrolysis of ATP; that is, part of the free energy of ATP hydrolysis is used to phosphorylate glucose:

(1) Glucose + Pi  ->  glucose 6 phosphate + H20                            Δ G′° = 13.8 kJ/mol

(2) ATP + H20    ->  ADP + Pi                                                                         Δ G′°= -30.5 kJ/mol

-------------------------------------------------------------------------------------------

Sum: Glucose + ATP -> glucose 6 phosphate + ADP

Calculate Keq at 25 °C for the overall reaction. For the ATP-dependent phosphorylation of glucose, what concentration of glucose is needed to achieve a 250 μm intracellular concentration of glucose 6-phosphate when the concentrations of ATP and ADP are 3.38 mm and 1.32 mm, respectively? Does this coupling process provide a feasible route, at least in principle, for the phosphorylation of glucose in the cell? Explain.  

(d) Although coupling ATP hydrolysis to glucose phosphorylation makes thermodynamic sense, we have not yet specified how this coupling is to take place. Given that coupling requires a common intermediate, one conceivable route is to use ATP hydrolysis to raise the intracellular concentration of Pi and thus drive the unfavorable phosphorylation of glucose by Pi. Is this a reasonable route? (Think about the solubility products of metabolic intermediates.)

(e) The ATP-coupled phosphorylation of glucose is catalyzed in hepatocytes by the enzyme glucokinase. This enzyme binds ATP and glucose to form a glucose-ATP-enzyme complex, and the phosphoryl group is transferred directly from ATP to glucose. Explain the advantages of this route.

Reference no: EM132439634

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