Reference no: EM132185897

On a piano, each key has a frequency, and each subsequent key (black or white) is a known amount higher. Ex: The A key above middle C key has a frequency of 440 Hz. Each subsequent key (black or white) has a frequency of 440 * rn, where n is the number of keys from that A key, and r is 2(1/12). Given an initial frequency, output that frequency and the next 3 higher key frequencies. If the input is 440, the output is: 440 493.883 523.251 554.365.

Note: Include one statement to compute r = 2(1/12) using the pow function, then use r in the formula fn = f0 * rn. (You'll have three statements using that formula, different only in the value for n).

(Note 4/17/17: A student noticed that our example and test cases are skipping n=1, starting instead with n=2. We won't change the lab right now, so just assume you've been asked for steps n=2, 3, and 4.)

starting code:

#include <iostream>

#include <cmath>

using namespace std;

int main() {

  int startingFrequency; 

  /* start code here. Include the math library above first. */

  return 0;

}