If we have a solution that contains 0022 m calcium and 0014

Reference no: EM13384611

If we have a solution that contains 0.022 M Calcium and 0.014 Magnesium and we have to use potassium hydroxide to selectively precipitate one of the ions, while leaving the other ion in the solution.

A) Which metal will precipitate first? ( this metal will be referred to as " first ion")

B) What minimum concentration of KOH is necessary to begin precipitation of "first ion" ?

C) What molarity of "first ion" remains in solution at the point when the second ion begins to precipitate ?

D) As we set up the second trial for this same experiment, we realised that we ran out of potassium hydroxide. All we have in the storage cabinet is potassium carbonate. Would this be a good titrant to use for the selective precipitation? Why or why not ? ( Ksp of Mg(OH)2 = 6.3 *10^-10, Ksp of Ca(OH)2 = 6.5 * 10^-6

Reference no: EM13384611

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