If 1200 grams of the metal m results in the formation

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An unknown metal M was converted to the sulfate,M2(SO4)3. A solution of this metalsulfate was treated with excess barium chloride solution to give abarium sulfate precipitate.
Reaction: M2(SO4)3(aq) + 3BaCl2 (aq) ---> 2 MCl3(aq) + 3BaSO4 (s)

If 1.200 grams of the metal, M results in the formation of6.026 grams of the barium sulfate product, what is the atomic weight of the unknown metal, M? What is the Metal?

Reference no: EM13636284

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