Reference no: EM1386829
1. There is a hybridization event between two different species with the same chromosome number. The hybrids are sterile. This is because:
Select one:
a.
There is too much nondisjunction during meiosis, so no viable gametes are produced.
b.
There are no homologous chromosomes, so the gametes are inviable.
c.
There is an unbalanced (odd) number of chromosomes, so the gametes are inviable.
d.
Meiosis does not take place in hybrids, so no gametes are produced.
2. A species of butterfly has 21 chromosomes, but all the closely related species have 22. This change in chromosome number may have been caused by a:
Select one:
a.
Paracentric inversion
b.
Deletion
c.
Robertsonian translocation
d.
Pericentric inversion
3. Approximately ______ of the gametes produced by an individual heterozygous for an inversion will be nonviable.
Select one:
a.
half
b.
an eighth
c.
a quarter
d.
none
e.
all
4. A garden pea contains two chromosomes: ABDEFG-HM and abdefh-gm (- indicates centromere). If crossing over occurred between gene G and the centromere on one chromatid of each homologous chromosome, what recombinant gametes would be produced?
Select one:
a.
ABDEFG-HM, abdefh-gm
b.
ABDEFH-gfedba, mh-GM
c.
ABDEFG-hfedba, mg-HM
d.
AB-DEFG-hm, abdefhgm
5. A fruit fly is heterozygous for deletion. Despite having dominant, functional alleles on one chromosomes, the fly still does not develop normally. This is an example of:
Select one:
a.
Duplicate genes
b.
Pseudodominance
c.
Hemizygosity
d.
Inversions
e.
Haploinsufficiency