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A shaft 100 mm diameter (D) runs in a bearing 200 mm long (L). The two surfaces are separated by an oil film 2.5 mm thick (c). Take the oil viscosity (miu) as 0.25 kg/ms.If the shaft rotates at a speed of (N) revolutions per minute.
a) Show that the torque exerted on the bearing is given as:
Torque = ((miu) * pi^2 *.N * L * D^3) / (120 * c).
b) How to show the torque expression step by step?
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