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Can you please solve this for me. I do know the concept, but the answer I get does not match with the one provided. Calculate the pH at equivalence point when 40.0 ml of 0.50 M aniline is titrated with 30.0 ml of 0.67 M HBr. For aniline Kb=3.8x10exp-10 thanks answer should be pH=2.85
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Calculate the pH at equivalence point when 40.0 ml of 0.50 M aniline is titrated with 30.0 ml of 0.67 M HBr. For aniline Kb=3.8x10exp
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