How to calculate the ph of the resulting solution

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Reference no: EM13298264

Consider the titration of 100.0 mL of 0.100 M H2NNH2 (Kb = 3.0 10-6) by 0.200 M HNO3. Calculate the pH of the resulting solution after the following volumes of HNO3 have been added. (e) 50.0 mL (f) 100.0 mL Show the work please. The problem I am having is I was able to calculate these when it was 20, 25, 40 mL. What to do now that it is 50 mL (the amount of H3O+ and H2NNH2 are the same) and the 100 mL (which is excess H+)?

Reference no: EM13298264

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