How much precipitate in moles would be recovered

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For the reactions shown below, we added 2.25 mL of 0.0540 M HCl to a test tube containing one of the two cations (Ag+ or Pb2+) and recovered 0.0174 g of precipitate.

AgNO3(aq) + HCl(aq) → AgCl(s) + HNO3(aq)

Pb(NO3)2(aq) + 2 HCl(aq) → PbCl2(s) + 2 HNO3(aq)

How much precipitate in moles would be recovered theoretically if the ion was Ag+? (Enter an unrounded value. Use at least one more digit than given.) (in mol)

How much precipitate in moles would be recovered theoretically if the ion was Pb2+? (Enter an unrounded value. Use at least one more digit than given.) (in mol)

How much precipitate in grams would be recovered theoretically if the ion was Ag+? (in g)

How much precipitate in grams would be recovered theoretically if the ion was Pb2+? (in g)

Based on the precipitate amount recovered, which of the two ions was in the unknown? Ag+ OR Pb2+

Reference no: EM131877855

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