How many grams of carbon were present in the original sample

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The female silkworm moth produces a sex attractant called bombykol, which is composed of 80.61% carbon, 12.68% hydrogen, and 6.71% oxygen.

(a) What is the empirical formula of bombykol?

(b) If the molecular weight of bombykol is 238.4 amu, what is the molecular formula?

(c) If 5.698 g of bombykol is burned in excess oxygen to form 16.83 g of CO2 and 6.452 g of H2O, how many grams of carbon were present in the original sample?

Reference no: EM13226282

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How many grams of carbon were present in the original sample : (b) If the molecular weight of bombykol is 238.4 amu, what is the molecular formula (c) If 5.698 g of bombykol is burned in excess oxygen to form 16.83 g of CO2 and 6.452 g of H2O, how many grams of carbon were present in the original sample
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