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From long experience, it is known that the time it takes to do an oil change and lubrication job on a vehicle has a normal distribution with a mean of 17.8 minutes and a standard deviation of 5.2 minutes. An auto service shop will give a free lube and oil change service to any customer who must wait beyond the guaranteed time to complete the work. If the shop does not want to give more than 1% of its customers a free lube and oil change service, how long should the guarantee be? Round appropriately to the minute.
A probability value of .25 means that an event will occur:
You've been recently hired as a marketing analyst in an advertising agency. You are assigned the task of assessing the impact of direct marketing promotions.
Which is the estimated or dear proportion of defective cups in the population?
Scenario: Dole Pineapple, Inc., is concerned that the 16-ounce can of sliced pineapple is being overfilled. Assume the standard deviation of the process is .03 ounces.
An occupational health study was carried out to evaluate the health status of workers. The response is forced expiratory volume (FEV), a measure of respiratory function
Suppose 94 percent of the items have lives exceeding 2000 h and 3.51 percent have lives exceeding 16,240 h. Find the mean and standard deviation of the service life.
Overall, 230 people correctly guess which is the low calorie product. Is there evidence of a difference in taste between the two products?
In a market study for Target, a researcher found that 70% of customers are repeat customers. If 14 customers are selected at random, find the probability of getting.
Explain what these terms mean in describing the distribution of the sales reps' salaries.
A researcher is evaluating the influence of a treatment using a sample selected from a normally distributed population with a mean of µ = 80 and a standard deviation of σ = 20. The researcher expects a 12 point treatment effect and plans to use a ..
Consider that you are a line manager in your current Corporation. There is a 0.50 probability that you will be promoted this year. There is a 0.65 probability that you will get a promotion or a raise. The probability of getting a promotion and a r..
Standard deviation of 10 pounds.. Find the probability, P(W
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