How far will it coast back up the ramp

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Reference no: EM13289373

Collision derivation problem. A car is released from rest on a frictionless inclined plane (Figure 5.3). EXAMPLES: Calculate the momentum pi at the end of the plane in terms of the measured quantities x, y, L, and m. Assume is very small so that h/L is approximately equal to y/x. (Hint: use conservation of energy and the fact that K=12mv2=p22m.) [Answer: p1=m(2gyLi/x)^1/2] If a car suffers a nearly elastic collision it will coast back up the ramp a distance Lf before reversing direction. What is the momentum pf immediately following the collision? The general expression for the change in momentum suffered in a collision is is = - . What is p (the magnitude of ) in terms of x, y, Li, Lf, and m? [Answer: delta p= p1-(-pf)=m(2gy/x)^0.5((Li)^0.5+(Lf)^0.5))] This is the expression you should use in the experiment. Make sure you understand how to derive these equations. QUESTION: If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 20/105, the initial displacement is 2.15 m, and the change in momentum is 0.62 kg*m/s, how far will it coast back up the ramp before changing directions?

Reference no: EM13289373

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