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How do I determine the exact value of sin 15°?
a) Start by drawing a right triangle that has angle 15-75-90 that has a side length x units that is opposite the 15° angle and a hypotenuse that is 1 unit
b) Break the triangle into an isosceles triangle and 30-60-90 triangle and write unknown sides in terms of x
c) Use this triangle to determine the exact value of sin 15°
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