Given that 240ml of 0170 m sodium iodide reacts with 0209m

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Reference no: EM13383839

Given that 24.0mL of 0.170 M sodium iodide reacts with 0.209M mercury(II) nitrate solution according to the unbalanced equation:

Hg(NO3)2 + NaI gives HgI2 + NaNO3

a) what volume of Hg(NO3)2 is required for complete precipitation?

b) what is the mass of HgI2 precipitate?

Reference no: EM13383839

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