Given k 103 x 10 -3 for h2sg h2g s2g at 750 degrees

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Given K = 1.03 X 10 -3 for H2S(g) H2(g) +S2(g) at 750 degrees Celsius. How many moles of S2 would you have to have at equilibrium in a 3.68 liter box in which there are 1.63 moles of H2S and 0.864 moles H2.

Reference no: EM13639374

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