Give the z statistic and the p-value

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Of the 460 respondents in a Christmas tree market survey, 41% had no children at home and 59% had at least one child at home. The corresponding figures for the most recent census are 48% with no children and 52% with at least one child. Test the null hypothesis that the telephone survey technique has a probability of selecting a household with no children that is equal to the value obtained by the census. Give the z statistic (rounded to two decimal places) and the P-value. What do you conclude? (Use (alpha) = 0.10.) z = ? P-value =?

Reference no: EM13138865

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