Genetic assignment

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Reference no: EM13536090

Genetic assignment

Question 1.1. In hamsters black coat color (B) is dominant to white coat color (b). A homozygous black hamster,BB, is mated with a white (bb)hamster. What will be the genotype ratio of their offspring?
100% black
100% Bb
1/2 black, 1/2 white
1/2 Bb and 1/2 bb


Question 2.2. In hamsters black coat color (B) is dominant to white coat color (b). A homozygous black hamster,BB, is mated with a white (bb)hamster. What will be the phenotype ratio of their offspring?
100% black
100% Bb
1/2 black, 1/2 white
1/2 Bb and 1/2 bb


Question 3.3. In hamsters black coat color (B) is dominant to white coat color (b). A homozygous black hamster,(BB) is mated with a heterozygous black (Bb)hamster. a) What will be the genotype ratio of their offspring?
100% black
100% Bb
1/2 black, 1/2 white
1/2 BB and 1/2 Bb


Question 4.4. In hamsters black coat color (B) is dominant to white coat color (b). A homozygous black hamster,(BB) is mated with a heterozygous black (Bb)hamster. a) What will be the phenotype ratio of their offspring?
100% black
100% Bb
1/2 black, 1/2 white
1/2 BB and 1/2 Bb


Question 5.5. In hamsters black coat color (B) is dominant to white coat color (b). A heterozygous black hamster, is mated with a heterozygous black hamster, a hybrid cross. a) What will be the genotype ratio of their offspring?
1/2 BB and 1/2 Bb
1/4 BB, 1/2 Bb, and 1/4 bb
100% black
3/4 black to 1/4 white


Question 6.6. In hamsters black coat color (B) is dominant to white coat color (b). A heterozygous black hamster, is mated with a heterozygous black hamster. a) What will be the phenotype ratio of their offspring?
1/2 BB and 1/2 Bb
1/4 BB, 1/2 Bb, and 1/4 bb
100% black
3/4 black to 1/4 white


Question 7.7. In hamsters black coat color (B) is dominant to white coat color (b). A heterozygous black hamster, is mated with a white hamster. a) What will be the genotype ratio of their offspring?
1/2 BB and 1/2 Bb
1/2 Bb and 1/2 bb
1/4 BB, 1/2 Bb, 1/4 bb
100% Bb


Question 8.8. In hamsters black coat color (B) is dominant to white coat color (b). A heterozygous black hamster, is mated with a white hamster. a) What will be the phenotype ratio of their offspring?
100% black
1 :1 black to white
3:1 black to white
all white


Question 9.9. In humans brown eyes is dominant to blue eyes. a) If a brown-eyed man married a blue-eyed woman and they had 4 kids, all with brown eyes, can we definitely conclude that the man was homozygous for brown eyes? Explain your answer.

10. a) In a paternity suit a woman claims that Jim is the father of her child. The child has type O blood. What blood type would Jim have to have for us to be certain that he was NOT the father? (Remember that in blood types type O is recessive, what does that tell you about the child's genotype? the parents?) See Unit 9 reading for discussion of blood types and inheritance. Also under chapter 11 on the textbook website, MediaLab investigation 2 on blood types.
Type A
Type B
Type AB
Type O


Question 11.11. In a paternity suit a woman claims that Jim is the father of her child. The child has type AB blood. What blood type would Jim have to have for us to be certain that he was NOT the father?
Type A
Type B
Type AB
Type O


Question 12.12. Can a type O child have a father with type A blood?
yes
no


Question 13.13. Explain question 12.



Question 14.14. Can a type AB child have a father with type A blood?

yes
no


Question 15.15. Can a type B child have a father with type O blood?
yes
no


Question 16.16. Can a type O child have parents one with type A and the other with type B blood?
yes
no


Question 17.17. Explain your answer to #16


Question 1.1. Which organism did Mendel use to work out the laws of segregation and independent assortment?
the fruit fly
Neurospora
the garden pea
the chicken
E. coli


Question 2.2. Diploid organisms
have corresponding alleles on homologus chromosomes
are usually the result of the fusion of two haploid gametes
have two sets of chromosomes
have pairs of homologous chromosomes
all of these


Question 3.3. If R is domiannt to r, the offspring of the cross of RR with rr will
be heterozygous
display the same phenotype as the RR parent
display the same phenotype as the rr parent
have the same genotype as the RR parent
more than one of the above is correct


Question 4.4. Mendel found that the organisms expressing a recessive trait
were pure-breeding
appeared in the second generation of a cross between two parents with contrasting traits
disappeared after crossing with a purbred dominant trait
could be produced even if neither parent expressed the trait
all of these are true statements about recessive phenotypes


Question 5.5. If tall ( D) is dominant to dwarf (d) and two heterozygous parents, Dd, are crossed, then what kind of offspring will be produced?
all intermediate forms
all tall
all dwarf
one half tall, one half dwarf
3/4 tall, 1/4 dwarf


Question 6.6. The F2 phenotypic ratio of a monohybrid cross, dominant to recessive, is
1:1
2:1
9:3:3:1
1:2:1
3:1


Question 7.7. If short hair (L) is dominant to long hair (l), and after crossing a short hair with a long hair and you have after several matings 24 short hair and 26 long hair offspring, what can you conclude about the short hair parent's genotype?
LL
Ll
ll
no conclusion can be made



Question 8.8. If a child belonged to blood type AB, he or she could not have been produced by which set of parents?
Type A mother and type B father
Type AB mother and type O father
Type AB mother and type B father
Type AB mother and type AB father


Question 9.9. A color blind woman and a man with normal vision whose father was colorblind, have a son. Colorblindness, in this case, is caused by an X-linked recessive gene. If only the male offspring are considered, the probability that their son is colorblind is
50%
75%
100%
0%


Question 10.10. Red-green colorblindness is an X-linked recessive trait in humans. What is the probability that a colorblind man and a woman with normal vision, whose father was colorbind, will have a colorblind daughter?
50%
75%
100%
0%

Reference no: EM13536090

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