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In an article entitled "Fuel Economy Calculations to Be Altered," James R. Healey indicated that the government planned to change how it calculates fuel economy for new cars and trucks. This is the first modification since 1985. It is expected to lower average mileage for city driving in conventional cars from 10% to 20%. AAA has forecast that the 2008 Ford F-150 would achieve 15.7 mile per gallon (mpg). The 2008 Ford F-150 was tested by AAA members driving the vehicle themselves and was found to have an average of 14.3 mpg. Assume that the mean obtained by AAA members is the true mean for the population of 2008 Ford F-150 trucks and that the population standard deviation is 5 mpg. The current method of calculating the mpg forecasts that the 2008 F-150 will average 16.8 mpg. Determine the probability that these same 100 AAA members would average more than 16.8 mpg while testing the 2008 F-150.
Suppose that X1,..,Xn form a random sample from the normal distribution with unknown mean M and unknown standard deviation S, and let m and s denote the MLEs of M and S. for the sample size n=17, find a value of k such that P(m > M +ks) = 0.95
A researcher conducts an experiment comparing two treatment conditions and obtains data with 10 scores for each treatment condition.
Write down the name of 4 parts of the regression equation.
Results of study are summarized below. Use a 5% level of significance and test claim that opinion is independent of brand.
Find a 90% confidence interval for the mean decibel level µ for this type of transit vehicle.
For each of following data sets, select the most suitable response from choices below the table. A strong negative linear relation exists.
Find the value for the correlation coefficient r.
A confidence interval increases in width as:
The point estimate for the difference between the proportions is:
Construct a 95% confidence interval estimate for the average waiting time of all the patients who visit this doctor. Assume the population of waiting times is normally distributed.
For a normal distribution, find the z-score value that separate the middle 90% of the distribution from the 10% in the tails.
You read a report that says, "On the basis of the simple random sample of 100 high school seniors that took the SATM test this year, a confidence interval for µ is found to be 512.00 ± 25.76." What was the confidence level used to calculate this..
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