Solution-Form aluminum chloride via the following reaction

Form aluminum chloride via the following reaction

Reference no: EM131323599

Hello, need help with the following chem questions.

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 24.0 g of aluminum and 29.0 g of chlorine gas.

1. If you had excess chlorine, how many moles of aluminum chloride could be produced from 24.0 g of aluminum?

2. If you had excess aluminum, how many moles of aluminum chloride could be produced from 29.0 g of chlorine gas, Cl2?

Reference no: EM131323599

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Form aluminum chloride via the following reaction : Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 24.0 g of aluminum and 29.0 g of chlorine gas.

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Form aluminum chloride via the following reaction

Reference no: EM131323599

Reference no: EM131323599

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