Five step hypothesis test for bellevue steel

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The production manager at Bellevue Steel, a manufacturer of wheelchairs, wants to perform a second analysis of the number of defective wheelchairs produced on the day shift and afternoon shift. A sample of the production from 6 day shifts and 8 afternoon shifts revealed the following number of defects.

At the 0.05 significance level, is there a difference in the mean number of defects per shift?

Day 10 9 6 6 8 9

Afternoon 8 10 7 5 4 10 5 6

1. State the null and alternate hypotheses.

2. What is the decision rule?

3. What is the value of the test statistic?

4. What is your decision regarding the null hypothesis?

5. What is the p-value?

6. Interpret the result.

Reference no: EM13109887

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