Find the total time from launch to maximum height

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Reference no: EM13704959

Solve the all parts of following question:

Question: A ball is launched upward from the bottom of a pool as shown in the figure. It undergoes two parts of motion.

Part 1: It is launched from the bottom of the pool with an initial velocity of 10.0 m/s. and reaches the surface of the pool with a velocity of 6.00 m/s. The acceleration is constant, and equal to 12.0 m/s2 , downward.

Part 2: After leaving the surface, the ball continues to move up, but now it undergoes freefall motion.

Part A: Find the depth of the pool?

Part B: Find the maximum distance above the pool's surface the ball reaches?

Part C: Find the total time from launch to maximum height?

Please give a full detailed explanation of answer.

Reference no: EM13704959

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