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Reference no: EM132011321

A cycle consists of an isotherm (T=624 K) going from a volume of 2.87 liters to a volume 7.54 times as large. An isometric side then decreases the pressure. Finally an adiabatic side returns the gas to the initial conditions. Find the percent efficiency. C sub v = 5 , R = 2 cal/mole degree K.

31 *31.4 B. 233 C. 268 D. 282 E. 299

100-250*(1-X1**-.4)/LOG(X1)

100-250*(1-7.54**-.4)/log(7.54)

31.407180675

Reference no: EM132011321

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