Find the p-value of a two-tailed test

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Reference no: EM13884262

-In a test of the hypothesis Ho: N= 50 versus Ha: ≠ 50, a sample of N= 50 observations possessed mean × (x bar) = 50.7 and standard deviation s= 4.1. The P value is: P = __ (rd. to 4 decimal places).

-In a study it was found that the average age of cable TV shoppers was 51 years. Suppose you want to test the null hypothesis Ho: µ = 51, using a sample of N= 60 cable TV shoppers.

a. Find the p-value of a two-tailed test if x (x bar) =51.8 and s =10.4. P= ___ (rd. to 4 dec. places).

b. Find the p-value of an upper-tailed test if x (x bar) = 51.8 and s= 10.4. P= ___ (rd. to 4 dec. places).

-Independent random samples from normal populations produced the results shown in the table:
Sample 1: 1.5, 1.9, 1.8, 2.2, 2.4. Sample 2: 3.5, 2.8, 3.1, 3.1.

a. Calculate the pooled estimate of σ2 . S 2p = ___ (Rd. 4 dec. places)

b. Find 95% confidence interval (CI)for (U1 - U2 ). CI is __, __ (rd. 2 dec. places).

-Hotel guests were randomly selected to rate service items on a 5-point scale. Males: Females:

n=124 n=119
x= 39.89 x= 39.38
s= 7.28 s= 7.43

Construct a 95% CI for the difference between the population mean service-rating scores given by male and female guests at the hotel. The 95% CI is __, __ (rd. 3 dec. places).

-Construct a 95% CI for (P1 - P2 ) in each situation.

a. N1 = 400; P^1 =0.63; N2 =400; P^2 =0.57 (^ symbol is above the P). 95% CI for (P1-P2) is __, __
b. N1 =180; p^1= 0.29; N2 =250; P^2 =0.26. 95% CI for (P1-P2) is __, __
c. N1 =100; P^1 =0.45; N2 =120; P^2 =0.59. 95% CI for (P1-P2) is __, __ (rd. nearest thousandth)

Reference no: EM13884262

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