Find the meand and standard deviation

Reference no: EM13197227

The normal daily human potassium requirement is in the range of 2000 to 6000 mg, with larger amounts required during hot summer weather. The amount of potassium in food varies, depending on the food. There is 630 mgs in a bannana. Suppose the distrivution of potassium in a bannana is normally distributed, withmean equal to 630 mg and standard deviation equal to 40 mg per bannana. You eat n=3 bannanas per day, and T is the total number of mgs of potasium you recieve from them.

A. Find the meand and standard deviation of T

B. find probability that your total daily intake of potasium from the three banannas will exceed 200ng

Reference no: EM13197227

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