Find the mean and standard deviation for janets waiting

Reference no: EM133411633

Case: Janet takes a bus to campus every weekday. Her bus arrives every 20 minutes. Suppose Janet shows up to the bus stop without looking at the schedule for the bus, so the amount of time she must wait for the bus is uniformly between 0 minutes and 20 minutes, with all of the times equally likely.
Let X = amount of time Janet must wait for the bus (in minutes)

a. How is X distributed? X ~ U(0, 20)

b. Find the mean and standard deviation for Janet's waiting times.

= (a + b)/2 = (0 + 20) / 2 = 10 mins = √(20-0)2/12= 5.77 min

c. Find the probability that Janet has to wait more than 8 minutes for the bus.

d. Find the probability that Janet has to wait 15 to 20 minutes for the bus.

Reference no: EM133411633

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