Find the magnitude of the current through the coils

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Reference no: EM13666551

Since the charge-to-mass ratio of the electron is known very exactly (1.759E11 C/Kg), the experiment you are about to do can be used to measure the magnitude of a uniform magnetic field. Electrons are accelerated from rest through a potential difference of 344 V. Then these electrons enter a uniform magnetic field that is perpendicular to the initial direction. Due to the interaction with the magnetic field, they move in a circular path of radius 0.741 centimeter.

a) Find what is the magnitude of the magnetic field?

The magnetic field was generated by a Helmholtz coil pair like the one described in the manual. You measure the coils and determine that the average diameter is 151 millimeter.

b) Find the magnitude of the current through the coils?

Assume a proton has a mass 1849 times greater than the electron. Its electric charge is the similar magnitude as that of the electron, but it is positive instead of negative.

c) Find what voltage would the proton have to be accelerated through for it to move in the same circle as the electron in parts a and b?

Reference no: EM13666551

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