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A travel agnecy offers 4 different vacation packages to Europe. Their net profit for package 1 is 300, for package 2 it is 450, for package 3 it is 600, for package 4 it is 1000. From past experience they know that 30% of their customers purchase package 1, 25% of their customer purchase package 2, 20% of their customers purchase package 3 and 25% of their customers purchase package 4. Find the expected value or average profit per customer.
Chi-square test for independent attributes - Are the opinions on the tax cut proposal independent of party affiliation? Use a = 0.01
If one item is chosen at random, determine these probabilities. It is a TV
Plot a scatter diagram of the results with Depth of Water as the independent variable.
Describe appropriate treatment means μ1, μ2 and μ3. After that Test for statistically significant differences between these treatment means. Set α = 0.05.
Out of a random sample of 500 individuals who are planning to vote in a student council election, 260 plan on voting for Jefferson and 240 plan on voting for Smith.
The original concepts of analysis of variance came from the work of Sir Ronald A. Fisher, an English statistician. This technique, better known as ANOVA, has become one of the most commonly used research methods for testing differences among sever..
The standard deviation is around 2.8. How many students should be sampled to be within 0.5 drink of population mean with 95% probability?
We are interested in testing to find out whether the variance of the population is vitally more than 0.003
What is the probability that the mean breaking strength of the 3 untreated specimens is at least 25 pounds greater than the mean strength of the 3 treated specimens?
The lead time is 2 weeks.If you were asked to create an (R,s,S) policy for this, what parameters would you pick? Give your reasons.
Subscribe to Cool Teen and 35% subscribe to neither magazine, what is the probability that a randomly selected teenager subscribes to both magazines?
For a normal probability distribution, about 95 percent of the area under normal curve is within plus and minus two standard deviations of the mean and practically all (99.73 percent) of the area.
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