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In a report given by a popular magazine it was stated that 60% of young children have blood leadlevels that could impair their neurological development. Assuming that aclass in a school is a random sample from the population of all children atrisk, the probability that at least 5 children out of 10 in a sample taken from a school may have a blood level that may impair development is?
A random variable X that has pmf given by p(x) = 1/ (n+1) over the range Rx = {0,1,2,...,n} is said to have a discrete uniform distribution. Find the mean and variance of this distribution.
In terms of p , the researcher should test which of the following null and alternative hypotheses?
Employees of a local university have been classified according to gender and job type. The following table provides data about the employees.
Survey was mailed to a total of 400 students; 100 were randomly selected from each of the freshman, sophomore, junior and senior classes last semester. What sampling method was used?
Create a 90 percent confidence interval for the population proportion of all such firms with this as the primary motivation.
Shopping time: House wares. How much customers buy is a direct result of how much time they spend in a store. The mean shopping time for women accompanied by children in national house wares stores is 7.3 minutes.
Find the critical value, t0, to test the claim that the mean1>mean 2. Two samples are randomly selected and come from populations that are normal. The sample statistics are given below. Assume that standard deviation 2/1 is not equal standard devi..
Find the probability that not enough seats will be available. Is this probability low enough so that overbooking is not a real concern?
An advantage of the permutation test over the t test for a difference in means, can Permutation tests be used for tests when we believe the two populations differ under the null hypothesis.
The ANOVA procedure is a statistical approach for determining whether or not:
Collapse the response categories in the following tables so that it meets the assumptions of the chi-square test; than perform the test.
For a normal random variable X with mean 70 and standard deviation 10. Calculate the probability that 60 80}.
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