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alum [KAL(SO4)2 times xH2O] is used in food preparation, dye fixation and water purification. To prepare alum, aluminum is reacted with potassium hydroxide and the product with sulfuric acid.
1) A 0.6815g sample of alum is heated to drive off the waters of hydration, and the resulting KAL(SO4)2 weighs 0.3709 g. Determine the value of x AND the complete formula of alum.
2) when 0.7939g of aluminum is used, 8.570g of alum forms. what is the percent yield?
What impact does the presence of moisture in the unknown
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the equivalence point i know you need to use [A-]= moles of HA/(vol water added+vol NaOH added) and believe moles of HA=5.39x10^-3
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