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There are forty chromosomes in somatic cells of the house mouse. a) how many chromosomes does a mouse receive from its father? b) how many autosomes are present in a mouse gamete? c) how many sex chromosomes are in a mouse ovum? d) how many autosomes are in somatic cells of a female?
Digestion of the oligonucleotide, AGUACAA, by pancreatic RNase would yield what products. make a restriction map for this plasmid.
These items are to be examined under a microscope. Sketch the following given specimen: gametophyte/ sporphyte, Closeup of sporangia.
Traditionally, it was thought that nucleus was the control center of the cell. Recent discoveries though, indicate that the nucleus in eukaryotes is merely a repository of genetic data.
It is not normal to administer a pure drug to a patient. Almost all the drugs are administered in form of a medicine. A medicine is a mixture of one or more drugs combined or formulated with the other inactive materials known as excipients.
The small intestine is specialized for absorption by the huge number of villi that line the intestinal wall. Villi have cells that generate intestinal enzymes which complete the digestion of peptides and sugars.
Estimate the value of the turnover number of the enzyme invertase, given that Rmax (Vmax) for invertase = 15.8 mmol·L-1·min-1 and [E]t = 4.8 ?
Think about the presence of hemoglobin in the catheter bag. What symptom would this loss of hemoglobin most strongly and immediately be linked to in the patient?
Describe why people confined to wheelchairs as of paralyzed lower limbs have thin, weak bones in their thighs and legs.
How many 10 micrometer yeast cells could fit across the field. In a guinea pig, black is dominant to brown, and solid colour is dominant to spotted. A heterozygous black, solid-coloured pig is mated with a brown, spotted pig.
Listing all the possible parent crosses for the ABO blood group. There must be 21 possible crosses.
An enzyme and its substrate are combined in a test tube but no product is formed. Another molecule is added to the tube, and now the product is formed at the normal rate. Give 2 reasons.what type of inhibition is working on the substrate.
Think about the problem of cone shape inheritance in chickens, where walnut, rose, pea, and single are observed as distinct phenotypes.
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