Find direct relationship between the heat and wave equations

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Reference no: EM13844539

Problem 1. Show that the wave equation does not, in general, satisfy a maximum principle.

Problem 2. For a solution u(x, t) of the wave equation

utt - uxx = 0,

the energy density is defined as e = (ut2 + ux2 )/2 and the momentum density is p = utux.

(a) Show that et = px and pt = ex.

(b) Show that both e and p also satisfy the wave equation.

Problem 3. Consider a traveling wave u(x, t) = f(x - at), where f is a given function of one variable.

(a) Show that if u is a solution of the wave equation utt - c2uxx = 0, then a = ±c (unless f is a linear function).

(b) Show that if u is a solution of the diffusion equation ut - kuxx = 0 then 

u(x, t) = C1exp (-a/k(x - at)) + C2

where C1 and C2 are arbitrary constants, and a ∈ R is arbitrary.

This exercise shows that the speed of propagation of travelling wave solutions of the wave equation is c, while for the heat equation, any arbitrary speed a ∈ R will do (i.e., we have infinite speed of propagation).

Problem 4. Here, we find a direct relationship between the heat and wave equations. Let u(x, t) solve the wave equation on the whole line, and suppose the second derivatives of u are bounded. Let

v(x, t) = c/√(4πkt). -∞e-s2c2/4kt u(x, s) ds.

(a) Show that v(x, t) solves the diffusion equation ut - kuxx = 0.

(b) Show that limt→0 v(x, t) = u(x, 0).

Problem 5. Find a formula for the solution of

ut - kuxx = 0 for x > 0 and t > 0

u = 0 for x > 0 and t = 0

u = 1 for x = 0 and t > 0.

(1)

Problem 6. Suppose u solves the heat equation

ut - kuxx = 0

for x ∈ R and t > 0

u = ? for x ∈ R and t = 0.

(2)

Show that if ? is odd, then for each t > 0 the function x → u(x, t) is odd. Show that the analogous result is true when ? is even.

Problem 7. Consider the diffusion equation on the half-line with Robin boundary condition:

ut - kuxx = 0 for x > 0 and t > 0

u = ? for x > 0 and t = 0

ux - hu = 0 for x = 0 and t > 0.

(3)

(a) Motivated by the method of odd and even extensions, we might guess that the solution u(x, t) is of the form

u(x, t) = 1/√(4πkt). -∞e-(x-y)2/4kt f(y)dy,

where

f(y) = ?(y), if y > 0

         g(-y), if y ≤ 0, (5)

and g is some (yet to be determined) function satisfying g(0) = ?(0). Recall that for the method of odd extension, g = -?, and for the method of even extension g = ?. Show that u given by (4) is the solution of (3) provided the function f - hf is odd.

(b) Show that f'- hf is odd if and only if

g'(y) + hg(y) = ?'(y) - h?(y) for all y ≥ 0.

(c) Suppose that ?(y) = y2 . Find g by solving the ODE from part (b) with initial condition g(0) = ?(0) assuming h = 0. What happens when h = 0?

Reference no: EM13844539

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