Reference no: EM132384288
A random sample of 322 medical doctors showed that 162 had a solo practice.
(a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.)
(b) Find a 98% confidence interval for p. (Use 3 decimal places.)lower limitupper limitGive a brief explanation of the meaning of the interval.
2% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.
98% of the all confidence intervals would include the true proportion of physicians with solo practices.
98% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.
2% of the all confidence intervals would include the true proportion of physicians with solo practices.
(c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice?
Report the margin of error.
Report the confidence interval.
Report p^ along with the margin of error.
Report p^.
What is the margin of error based on a 98% confidence interval? (Use 3 decimal places.)
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