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Fandango claim's that the average cost of a movie ticket is at least $8.75 for an adult, with a known variance of $0.25. To test this claim, a random sample of 75 tickets had a mean of $8.06. There is no reason to think the variance is any different in the sample. Based upon this information, can we reject Fandango's claim at the 5% level of significance
question it is known that the number of business failure in usa per hour is distributed as poisson with mean micro
For the following exercise, complete the following: Find the mean, median, and range for each of the two data sets. Find the standard deviation using the rule of thumb for each of the data sets.
Test the hypothesis that the observations come from a population having a Poisson distribution with mean .3.
Assume a steady smoker spends on average $20 with a standard deviation of $5 per week on cigarettes. What is the probability that a sample of 100 steady smokers spend between $19.50 and $21?
Exam is given to 20 randomly chosen students and their average length of t time needed to finish exam was 54 minutes with standard deviation of 5.99 minutes. Test instructor's claim at the 0.05 level of significance.
Does the scatterplot indicate that it's appropriate to calculate a correlation? Explain.- Describe the association between attendance and runs scored.
What is the amount of net income earned during the month of March?
Exercise gave data on height and whether or not a student had ever been bullied for 209 secondary school students in England.
A student is taking a multiple choice exam in which each question has four choices . Assume that the student has knowledge of a correct answer to any of the questions.
1.an instructor wanted to construct a confidence interval for the mean gpa of the students in his class. he used the
three balls are randomly chosen without replacement from an urn containing 4 red 3 white and 3 blue balls. suppose that
Find the population mean μ.- Use technology to select 50 random samples of size 10 from this population. Find the sample mean for each sample.
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