Explian how many moles of amide ions are in liquid ammonia

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Liquid ammonia ionizes to a slight extent. 2NH3(l) > NH4^(+) + NH2^(-). At -50 degrees Celsius, its ion product is K(NH3) = [NH4^(+)][NH2^(-)] = 10^(-30). How many moles of amide ions, NH2^(-), are present per mm^3 of pure liquid ammonia?

Reference no: EM13332209

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