Explain while it is titrated to the second equivalence point

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Compute the pH of a solution of 30.0mL of 0.0580 m malonic acid (H2C3H3O4) while it is titrated to the second equivalence point with 0.100 M KOH. (For H2C3H2O4 Ka1: 1.5*10^-3 and Ka2:2.0*10^-6)

Reference no: EM13665861

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Explain while it is titrated to the second equivalence point : Compute the pH of a solution of 30.0mL of 0.0580 m malonic acid (H2C3H3O4) while it is titrated to the second equivalence point with 0.100 M KOH. For H2C3H2O4 Ka1: 1.5*10^-3 and Ka2:2.0*10^-6
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